说明:
前端使用:vue3.0
前后端对接数据格式:无非就是前端把后端返回的数据处理为自己想要的格式,或者,后端给前端处理好想要的格式;
针对前后端的柱状图,趋势图等数据对接,前端一般需要数组格式;
我们之前返回的数据格式是LIst Map
举例:动态数据统计思路案例(动态,排序,containsKey)五(117)
如图所示;
而我们需要数组格式:
后端代码处理:
@Overridepublic Map<String,Object> getTimeData(HttpServletRequest request, Map<String, Object> paramMap) {List<Map<String,Object>> list = getCountData(request,paramMap);list = list.stream().filter(e -> (e.get("status").equals("关闭"))).collect(Collectors.toList());// Map存储:(region,num),num为相同region的加和;Map<String,Object> regionMap = new HashMap<>();// Map存储:(region,统计次数),统计次数为相同region的次数;Map<String,Object> countMap = new HashMap<>();for (int i = 0; i < list.size(); i++) {String region = String.valueOf(list.get(i).get("region"));String num = String.valueOf(list.get(i).get("processTime"));// regionMap包含region:将region当作key;if(regionMap.containsKey(region)) {String key = region;String value = String.valueOf(regionMap.get(key)); // 从regionMap获取value值;即地域对应的num值;regionMap.put(region, Double.parseDouble(value) + Double.parseDouble(num));}else { // 不包含,直接存进去regionMap.put(region, num);}// countMap包含region:将region当作key;if(countMap.containsKey(region)) {String key2 = region;String value2 = String.valueOf(countMap.get(key2)); // 从countMap获取value值;即地域对应的统计次数值;countMap.put(region, Integer.valueOf(value2) + 1);}else { // 不包含,直接存进去countMap.put(region, 1);}}List<String> regionList = new LinkedList<String>(); // 地域List<String> numberList = new LinkedList<String>(); // 数值List<String> countList = new LinkedList<String>(); // 统计次数List<String> avgList = new LinkedList<String>(); // 平均值// 封装地域集合:(北京,数值和)Iterator<Map.Entry<String, Object>> it = regionMap.entrySet().iterator();while(it.hasNext()){Map.Entry<String, Object> entry = it.next();String key = entry.getKey();String value = String.valueOf(entry.getValue());regionList.add(key);numberList.add(value);}// 封装统计次数集合:(北京,统计次数)Iterator<Map.Entry<String, Object>> it2 = countMap.entrySet().iterator();while(it2.hasNext()){Map.Entry<String, Object> entry = it2.next();String value = String.valueOf(entry.getValue());countList.add(value);}// 计算平均值:封装集合avgListif(numberList.size() == countList.size()) {for (int i = 0; i < numberList.size(); i++) {double fenzi = Double.parseDouble(numberList.get(i));int fenmu = Integer.valueOf(countList.get(i));if(fenmu > 0) {Double x = fenzi/fenmu;// double类型的数据当分母的数值趋近0的时候,返回来的数值就是一个NAN:if(Double.isNaN(x)){x = 0.0;}avgList.add(String.valueOf(x));}}}// 最终输出集合:List<Map<String,Object>> resultList = new ArrayList<>();// 根据地域集合与平均值集合封装新集合resultList:if(regionList.size() == avgList.size()) {for (int i = 0; i < regionList.size(); i++) {Map<String,Object> map = new HashMap<>();map.put("title",regionList.get(i));map.put("value",avgList.get(i).substring(0,avgList.get(i).indexOf(".")+2));resultList.add(map);}}//排序:value值大的Map往前排,斌且插入新字段:sortValue,代表序列;Double[] valueSort = new Double[resultList.size()];String[] titleSort = new String[resultList.size()];// 排序后最终输出集合:List<Map<String,Object>> listFinal= new ArrayList<>();// 获取排序的数组:for (int i = 0; i < resultList.size(); i++) {valueSort[i] = Double.parseDouble(String.valueOf(resultList.get(i).get("value")));titleSort[i] = String.valueOf(resultList.get(i).get("title"));}// 数组排序:BubblSortUtils.bubbleSortDescMultipleDouble(valueSort,titleSort);// 数组封装listFinal:for (int i = 0; i < valueSort.length; i++) {String ch = String.valueOf(titleSort[i]);for (int j = 0; j < resultList.size(); j++) {String value = String.valueOf(resultList.get(j).get("title"));if(ch.equals(value)){listFinal.add(resultList.get(j));}}}// listFinal中添加排序字段:sortValueString[] A = new String[listFinal.size()];String[] B = new String[listFinal.size()];for (int i = 0; i < listFinal.size(); i++) {listFinal.get(i).put("sortValue",listFinal.size()-i);A[i] = String.valueOf(listFinal.get(i).get("title"));B[i] = String.valueOf(listFinal.get(i).get("value"));}Map<String,Object> restMap = new HashMap<>();restMap.put("title",A);restMap.put("value",B);return restMap;}
备注:以上代码可简化处理,写这么多是为了明确每个过程,提供数据处理的拓展思路;
代码修改位置:
1.最终返回值由List Map改为数组返回:
2.修改接口返回值类型:由List Map修改为Map
最后返回值修改如下:
// listFinal中添加排序字段:sortValueString[] A = new String[listFinal.size()];String[] B = new String[listFinal.size()];for (int i = 0; i < listFinal.size(); i++) {listFinal.get(i).put("sortValue",listFinal.size()-i);A[i] = String.valueOf(listFinal.get(i).get("title"));B[i] = String.valueOf(listFinal.get(i).get("value"));}Map<String,Object> restMap = new HashMap<>();restMap.put("title",A);restMap.put("value",B);return restMap;
Postman测试:
这样前端就可以直接获取使用了,返回的数组里面也是经过排序处理的;