2023每日刷题（六十九）

Leetcode—86.分隔链表

实现代码

/*** Definition for singly-linked list.* struct ListNode {*     int val;*     struct ListNode *next;* };*/
struct ListNode* partition(struct ListNode* head, int x) {struct ListNode* small = (struct ListNode*)malloc(sizeof(struct ListNode));struct ListNode* big = (struct ListNode*)malloc(sizeof(struct ListNode));small->next = NULL;big->next = NULL;struct ListNode* r1 = small;struct ListNode* r2 = big;while(head != NULL) {if(head->val < x) {r1->next = head;r1 = head;} else {r2->next = head;r2 = head;}head = head->next;}r2->next = NULL;r1->next = big->next;return small->next;
}

运行结果

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