给你两个字符串：ransomNote 和 magazine ，判断 ransomNote 能不能由 magazine 里面的字符构成。如果可以，返回 true ；否则返回 false 。magazine 中的每个字符只能在 ransomNote 中使用一次。

示例 1：

输入：ransomNote = "a", magazine = "b"
输出：false

示例 2：

输入：ransomNote = "aa", magazine = "ab"
输出：false

示例 3：

输入：ransomNote = "aa", magazine = "aab"
输出：true

#include <stdio.h>
#include <stdbool.h>
#include <string.h>bool canConstruct(char* ransomNote, char* magazine) 
{int len1 = strlen(ransomNote);int len2 = strlen(magazine);if(len1 > len2){return false;}int start = 0;int end = 0;for(int j = 0;j < len2;j++){int s = j;while(ransomNote[start] == magazine[j] && ransomNote[start] != '\0'){start++;j++;end++;}if(end == len1){return true;}else{start = 0;end = 0;j = s;}}return false;}int main()
{char ransomNote[] = "aa";char magazine[] = "bbabaa";int a = canConstruct(ransomNote,magazine);printf("%d\n",a);return 0;
}