通俗易懂,就是被复制的和复制的是同一片地址，而深拷贝的话是两个不同的地址

深拷贝与浅拷贝:c++不知道，你用一把钥匙来构造另一把钥匙的目的是什么

                        最朴素的复制一把一模一样的钥匙        

                        两把钥匙指向同一空间

#include <iostream>
#include <cstring>
using namespace std;class Student
{char *name;char sex;int id;
public:Student(){cout<<"默认构造"<<endl;}Student(const char *name=" ", char sex=0, int id=0){int len = strlen(name);this->name = new char[len+1];strcpy(this->name, name);this->sex = sex;this->id = id;cout<<"构造"<<endl;}Student(const Student& that){name=that.name;  //两个name使用的是同一块地址sex=that.sex;id=that.id; //默认拷贝构造cout<< &that.name<<" "<<&name<<endl; /*int len=strlen(that.name);this->name=new char[len+1];strcpy(this->name, that.name);this->sex=that.sex;this->id=that.id;       //深拷贝（开辟内存cout<< &that.name<<" "<<&name<<endl;cout<<"拷贝构造"<<endl;         //为了s1和s2不共用一块内存*/}~Student(){delete[] name;cout<<"析构"<<endl;}Student& operator=(const Student& that){if(this!=&that) //防止自拷贝{delete[] name;int len=strlen(that.name);name=new char[len+1];strcpy(name, that.name);sex=that.sex;id=that.id;}cout<<"赋值"<<endl;return *this;}void show(void){cout<<&name<<" "<<name<<endl;}
};//没有开辟空间，会重复释放空间，导致段错误
int main()
{Student s1("ke19",'m',1001);Student s2(s1);// Student s3 ;//s3=s1;s1.show();s2.show();}