题目：
题解：
class Solution:def compareVersion(self, version1: str, version2: str) -> int:n, m = len(version1), len(version2)i, j = 0, 0while i < n or j < m:x = 0while i < n and version1[i] != '.':x = x * 10 + ord(version1[i]) - ord('0')i += 1i += 1 # 跳过点号y = 0while j < m and version2[j] != '.':y = y * 10 + ord(version2[j]) - ord('0')j += 1j += 1 # 跳过点号if x != y:return 1 if x > y else -1return 0
