题目:
题解:
int numberOfArithmeticSlices(int* nums, int numsSize) {if (numsSize == 1) {return 0;}int d = nums[0] - nums[1], t = 0;int ans = 0;// 因为等差数列的长度至少为 3,所以可以从 i=2 开始枚举for (int i = 2; i < numsSize; ++i) {if (nums[i - 1] - nums[i] == d) {++t;} else {d = nums[i - 1] - nums[i];t = 0;}ans += t;}return ans;
}