from tkinter import BOTH,FIRST,LAST,GROOVE,FLAT
import os, random
import tkinter as tk
import tkinter.messagebox
import numpy as np
from PIL import Image, ImageTk
import time
from playsound import playsoundclass MainWindow():__gameTitle = "连连看游戏"__windowWidth = 600__windowHeigth = 500__gameSize = 10 # 游戏尺寸__iconKind = __gameSize * __gameSize / 4 # 小图片种类数量__iconWidth = 40__iconHeight = 40__map = [] # 游戏地图__delta = 25__isFirst = True__isGameStart = False__formerPoint = NoneEMPTY = -1NONE_LINK = 0STRAIGHT_LINK = 1ONE_CORNER_LINK = 2TWO_CORNER_LINK = 3__images = []#蒙板阴影图像__level = 1#游戏关卡__point_position = {}__score = 0def __init__(self):self.__root = tk.Tk()self.__root.title(self.__gameTitle)self.centerWindow(self.__windowWidth, self.__windowHeigth)self.__root.minsize(460, 460)self.__addComponets()self.new_game()self.__root.mainloop()#菜单栏中添加一个叫“游戏”的菜单项def __addComponets(self):#菜单栏self.menubar = tk.Menu(self.__root, bg="lightgrey", fg="black")#子菜单self.file_menu = tk.Menu(self.menubar, tearoff=0, bg="lightgrey", fg="black")self.file_menu.add_command(label="新游戏", command=self.new_game, accelerator="Ctrl+N")self.menubar.add_cascade(label="游戏", menu=self.file_menu)self.__root.configure(menu=self.menubar)self.__root.bind('<Control-n>',self.new_game)#实现快捷键功能ctrl+N#self.canvas = tk.Canvas(self.__root, bg = '#D3D3D3', width = 450, height = 450,cursor="hand2")self.canvas.grid(row=0,column=0,sticky='N',pady = 5,rowspan=2,padx=(50,0))self.canvas.bind('<Button-1>', self.clickCanvas)#分数面板self.label_score = tkinter.Label(self.__root,width=10,height=2,font=('黑体',13,'bold'),fg="#802A2A",bg="#F5DEB3")self.label_score.grid(row=0,column=1)#显示当前可连接数self.label_linknums = tkinter.Label(self.__root,width=10,height=2,font=('黑体',13,'bold'),fg="#228B22")self.label_linknums.grid(row=1,column=1)'''判断两个接点之间是否能连通'''def __isLink(self,fromPoint,point):return self.isStraightLink(fromPoint,point) or self.isOneCornerLink(fromPoint,point) or self.isTwoCornerLink(fromPoint,point)'''获取提示，逻辑有点复杂，主要解决以下问题：1.获取当前地图上所有的图标；2.然后遍历，计算有多少对可连通的图标；3.如果有三个或者四个相同的图标可以相互连通，要进行判断，以勉出现重复计算。'''def getPromptPoint(self):_link_point = []_icons_arr = self.__map.flatten()#先转化为一维数组，便于操作for i in set(_icons_arr):if i == self.EMPTY: continue #忽略为空的坐标_arr = np.where(_icons_arr==i)[0]#元组的第一个元素，是由i元素的索引组成的数组if _arr.size == 4:#剩下4个相同图标_point1 = Point(int(_arr[0]%10),int(_arr[0]/10))# 计算x,y坐标_point2 = Point(int(_arr[1]%10),int(_arr[1]/10))_point3 = Point(int(_arr[2]%10),int(_arr[2]/10))_point4 = Point(int(_arr[3]%10),int(_arr[3]/10))#4个接点6条线，但最多只能计算2条线，再多就会出现重复计数if self.__isLink(_point1,_point2):_link_point.append((_point1,_point2))if self.__isLink(_point3,_point4):_link_point.append((_point3,_point4))elif self.__isLink(_point1,_point3):_link_point.append((_point1,_point3))if self.__isLink(_point2,_point4):_link_point.append((_point2,_point4))elif self.__isLink(_point1,_point4):_link_point.append((_point1,_point4))if self.__isLink(_point2,_point3):_link_point.append((_point2,_point3))elif self.__isLink(_point2,_point3):_link_point.append((_point2,_point3))elif self.__isLink(_point2,_point4):_link_point.append((_point2,_point4))elif self.__isLink(_point3,_point4):_link_point.append((_point3,_point4))    elif _arr.size == 2:#剩下2个相同图标_point1 = Point(int(_arr[0]%10),int(_arr[0]/10))# 计算x,y坐标_point2 = Point(int(_arr[1]%10),int(_arr[1]/10))if self.__isLink(_point1,_point2):_link_point.append((_point1,_point2))self.label_linknums['text'] = f"{len(_link_point)}连"print("_link_point",_link_point)return _link_pointdef centerWindow(self, width, height):#700 500screenwidth = self.__root.winfo_screenwidth()#窗口距离屏幕左边的宽screenheight = self.__root.winfo_screenheight()#窗口距离屏幕顶部的高size = '%dx%d+%d+%d' % (width, height, (screenwidth - width)/2, (screenheight - height)/2)self.__root.geometry(size)def add_score(self):self.__score += 2 #消除一对图标，分数加2self.set_label_text()def set_label_text(self):self.label_score['text'] = f"{self.__score}分"'''这个方法需要注意的积分问题：1.开始新游戏时，将积分清零；2.开始下一关时，将前一关的积分累积起来。'''def new_game(self, event=None,level=1,score = 0):self.__score = scoreself.set_label_text()self.__level = levelself.extractSmallIconList()self.iniMap()self.drawMap()self.getPromptPoint()self.__isGameStart = Truedef clickCanvas(self, event):if not self.__isGameStart:return# 确认有效点击坐标point = self.getInnerPoint(Point(event.x, event.y))if not point.isUserful() or self.isEmptyInMap(point):return#__isFirst在三种情况下为True，1.游戏开始的时候；2.同一个图标点击了两次；3.成功消除一组图标。if self.__isFirst:self.drawSelectedArea(point)self.__isFirst= Falseself.__formerPoint = pointelse:if self.__formerPoint.isEqual(point):#两次点击的是同一个图标self.__isFirst = Trueself.canvas.delete("rectRedOne")self.canvas.delete('image_mask')else:linkType = self.getLinkType(self.__formerPoint, point)if linkType['type'] != self.NONE_LINK:#画连接线self.draw_link_line(self.__formerPoint,point,linkType)playsound("music2.mp3")time.sleep(.5)# 显示画线的延迟self.ClearLinkedBlocks(self.__formerPoint, point)self.canvas.delete("rectRedOne")self.canvas.delete("linkline")self.canvas.delete('image_mask')#增加分数self.add_score()_link_point = self.getPromptPoint()self.__isFirst = Trueif len(_link_point) == 0:if self.isGameEnd():if tk.messagebox.askokcancel('确认操作', '是否进入下一关？'):self.__level = self.__level+1self.new_game(level = self.__level,score = self.__score)else:self.__isGameStart = Falseelse: #没有可连通图标，且当前地图上还有图标存在,游戏未结束时，打散当前地图tk.messagebox.showinfo("提示", "已没有可连通图标，需重新打散！")self.shuffleMap()self.drawMap()self.getPromptPoint()else:self.__formerPoint = pointself.canvas.delete("rectRedOne")self.drawSelectedArea(point)# 判断游戏是否结束def isGameEnd(self):for y in range(0, self.__gameSize):for x in range(0, self.__gameSize):if self.__map[y][x] != self.EMPTY:return Falsereturn True'''消除图像前，把两个图像之间的连接线画出来。'''def draw_link_line(self,formerPoint,point,linkType):if linkType['type'] == self.STRAIGHT_LINK:p1 = self.getOuterCenterPoint(formerPoint)p2 = self.getOuterCenterPoint(point)#arrow表示线的箭头样式，默认不带箭头，参数值 FIRST表示添加箭头带线段开始位置，LAST表示到末尾占位置，BOTH表示两端均添加self.canvas.create_line((p1.x, p1.y),(p2.x, p2.y),fill = 'red',tags = 'linkline',width=3, arrow=LAST)if linkType['type'] == self.ONE_CORNER_LINK:           corner1 = self.getOuterCenterPoint(linkType["p1"])p1 = self.getOuterFitCenterPoint(formerPoint,corner1)p2 = self.getOuterFitCenterPoint(point,corner1)self.canvas.create_line((p1.x, p1.y),(corner1.x, corner1.y),fill = 'red',tags = 'linkline',width=3)self.canvas.create_line((p2.x, p2.y),(corner1.x, corner1.y),fill = 'red',tags = 'linkline',width=3, arrow=FIRST)elif linkType['type'] == self.TWO_CORNER_LINK:corner1 = self.getOuterCenterPoint(linkType["p1"])corner2 = self.getOuterCenterPoint(linkType["p2"])p1 = self.getOuterFitCenterPoint(formerPoint,corner1)p2 = self.getOuterFitCenterPoint(point,corner2)self.canvas.create_line((p1.x, p1.y),(corner1.x, corner1.y),fill = 'red',tags = 'linkline',width=3)self.canvas.create_line((p2.x, p2.y),(corner2.x, corner2.y),fill = 'red',tags = 'linkline',width=3, arrow=FIRST)self.canvas.create_line((corner1.x, corner1.y),(corner2.x, corner2.y),fill = 'red',tags = 'linkline',width=3)self.canvas.update()'''提取小头像数组'''def extractSmallIconList(self):self.__icons = []imageSouce = Image.open(f"图片/new{self.__level}.png")for index in range(0, int(self.__iconKind)):#0-24region = imageSouce.crop((self.__iconWidth * index, 0, self.__iconWidth * index + self.__iconWidth - 1, self.__iconHeight - 1))self.__icons.append(ImageTk.PhotoImage(region))'''初始化地图 存值为0-24'''def iniMap(self):self.__map = [] # 重置地图_tmpRecords = []# 0-24，一共25个图标,每个图标出现4次,总共出现100次_total = self.__gameSize * self.__gameSize_tmpRecords = np.linspace(0, self.__iconKind, _total, endpoint = False,dtype=int) np.random.shuffle(_tmpRecords)#重新打散洗牌self.__map = _tmpRecords.reshape((10,10))#将一维数组100,转化为二维10*10'''初始化地图 存值为0-24，当前地图中，如果没有可连通路线、进入死局时，将现有的图标进行打散重新洗牌。'''def shuffleMap(self):_icons_arr = self.__map.flatten()#先转化为一维数组，便于操作self.__map = []#重置地图for i in set(_icons_arr):if i == self.EMPTY: continue_tuple = np.where(_icons_arr==i)[0]#元组的第一个元素，是由i元素的索引组成的数组self.__map.extend([i]* _tuple.size)#第i个图标出现的次数np.random.shuffle(self.__map)#洗牌_len = len(self.__map)_total = self.__gameSize * self.__gameSizeself.__map[_len:_total] = [self.EMPTY]*(_total-_len)#剩余元素置为空(-1)，填满至整个地图0-99self.__map = np.array(self.__map).reshape((self.__gameSize,self.__gameSize))#转化为二维数组10*10'''根据地图绘制图像1.在使用create_image()函数时，需要先通过Pillow库（或其他图片处理库）读取图片文件并生成图片对象，然后再将这个图片对象传递给create_image()函数，在指定的坐标位置将图片添加到画布上。2.canvas.create_image(x, y, image=图像对象, anchor=定位点)，x和y表示图像锚点在画布上的位置，即图像在画布上的左上角坐标。image参数是一个tkinter中的PhotoImage()对象，它可以指定要加载的图像文件。anchor参数是一个字符串，用于指定图像锚点的位置，可以是"nw"（左上角）、"n"（上）、"ne"（右上角）、"w"（左）、"center"（中心）、"e"（右）、"sw"（左下角）或"s"（下）。如果不指定anchor参数，则默认为“center”。'''def drawMap(self):self.canvas.delete("all")#字符串"all""是代表画布上所有项目的特殊标记for y in range(0, self.__gameSize):for x in range(0, self.__gameSize):point = self.getOuterLeftTopPoint(Point(x, y))if self.__map[y][x] != self.EMPTY:#打散重绘时，不再置空的图标self.canvas.create_image((point.x, point.y),image=self.__icons[self.__map[y][x]], anchor='nw', tags = 'im%d%d' % (x, y))'''根据两点不同的位置，获取对应边的中心连接点。例如目标图标在左边，就取靠左的一边的中点。如果连接目标在右边，就取靠右一边的中点坐标。'''def getOuterFitCenterPoint(self, formerPoint, corner):_formerPoint = self.getOuterCenterPoint(formerPoint)if _formerPoint.y>corner.y:fitCenterPoint = Point(self.getX(formerPoint.x) + int(self.__iconWidth / 2),self.getY(formerPoint.y))#顶边elif _formerPoint.y<corner.y:fitCenterPoint = Point(self.getX(formerPoint.x) + int(self.__iconWidth / 2),self.getY(formerPoint.y) + int(self.__iconHeight))#底边elif _formerPoint.y == corner.y:if _formerPoint.x > corner.x:fitCenterPoint = Point(self.getX(formerPoint.x),self.getY(formerPoint.y)+int(self.__iconHeight / 2))#左边elif _formerPoint.x < corner.x:fitCenterPoint = Point(self.getX(formerPoint.x) + int(self.__iconWidth),self.getY(formerPoint.y)+int(self.__iconHeight / 2))#右边return fitCenterPoint'''获取内部坐标对应矩形左上角顶点坐标'''def getOuterLeftTopPoint(self, point):return Point(self.getX(point.x), self.getY(point.y))'''获取内部坐标对应矩形中心坐标'''def getOuterCenterPoint(self, point):return Point(self.getX(point.x) + int(self.__iconWidth / 2), self.getY(point.y) + int(self.__iconHeight / 2))def getX(self, x):# x * 40 + 25return x * self.__iconWidth + self.__deltadef getY(self, y):return y * self.__iconHeight + self.__delta'''获取内部坐标'''def getInnerPoint(self, point):x = -1y = -1for i in range(0, self.__gameSize):x1 = self.getX(i)x2 = self.getX(i + 1)if point.x >= x1 and point.x < x2:x = ifor j in range(0, self.__gameSize):j1 = self.getY(j)j2 = self.getY(j + 1)if point.y >= j1 and point.y < j2:y = jreturn Point(x, y)'''创建一块蒙板，覆盖到选中的图形上'''def create_mask(self,x1, y1, x2, y2, **kwargs):#(0,0,0)代表黑色的RGB，127代表alpha透明度，(x2-x1, y2-y1)指长宽image = Image.new('RGBA', (x2-x1, y2-y1), (0,0,0,127))self.__images = [ImageTk.PhotoImage(image)]#这里一定要用一个实例变量存储，局部变量没有效果，原因不清楚self.canvas.create_image(x1, y1, image=self.__images[0], anchor='nw',tags = "image_mask")'''选择的区域变红，point为内部坐标'''def drawSelectedArea(self, point):pointLT = self.getOuterLeftTopPoint(point)pointRB = self.getOuterLeftTopPoint(Point(point.x + 1, point.y + 1))self.canvas.create_rectangle(pointLT.x, pointLT.y, pointRB.x - 1, pointRB.y - 1, outline = 'red', tags = "rectRedOne", width=2)#蒙板self.create_mask(pointLT.x, pointLT.y, pointRB.x - 1, pointRB.y - 1, fill='skyblue', alpha=.5,width=0)'''消除连通的两个块'''def ClearLinkedBlocks(self, p1, p2):self.__map[p1.y][p1.x] = self.EMPTYself.__map[p2.y][p2.x] = self.EMPTYself.canvas.delete('im%d%d' % (p1.x, p1.y))self.canvas.delete('im%d%d' % (p2.x, p2.y))'''地图上该点是否为空'''def isEmptyInMap(self, point):if self.__map[point.y][point.x] == self.EMPTY:return Trueelse:return False'''获取两个点连通类型'''def getLinkType(self, p1, p2):# 首先判断两个方块中图片是否相同if self.__map[p1.y][p1.x] != self.__map[p2.y][p2.x]:return { 'type': self.NONE_LINK }if self.isStraightLink(p1, p2):return {'type': self.STRAIGHT_LINK}res = self.isOneCornerLink(p1, p2)if res:return {'type': self.ONE_CORNER_LINK,'p1': res}res = self.isTwoCornerLink(p1, p2)if res:return {'type': self.TWO_CORNER_LINK,'p1': res['p1'],'p2': res['p2']}return {'type': self.NONE_LINK}'''直连'''def isStraightLink(self, p1, p2):start = -1end = -1# 水平if p1.y == p2.y:# 大小判断if p2.x < p1.x:start = p2.xend = p1.xelse:start = p1.xend = p2.xfor x in range(start + 1, end):if self.__map[p1.y][x] != self.EMPTY:return Falsereturn Trueelif p1.x == p2.x:if p1.y > p2.y:start = p2.yend = p1.yelse:start = p1.yend = p2.yfor y in range(start + 1, end):if self.__map[y][p1.x] != self.EMPTY:return Falsereturn Truereturn Falsedef isOneCornerLink(self, p1, p2):pointCorner = Point(p1.x, p2.y)if self.isStraightLink(p1, pointCorner) and self.isStraightLink(pointCorner, p2) and self.isEmptyInMap(pointCorner):return pointCornerpointCorner = Point(p2.x, p1.y)if self.isStraightLink(p1, pointCorner) and self.isStraightLink(pointCorner, p2) and self.isEmptyInMap(pointCorner):return pointCornerdef isTwoCornerLink(self, p1, p2):for y in range(-1, self.__gameSize + 1):pointCorner1 = Point(p1.x, y)pointCorner2 = Point(p2.x, y)if y == p1.y or y == p2.y:continueif y == -1 or y == self.__gameSize:if self.isStraightLink(p1, pointCorner1) and self.isStraightLink(pointCorner2, p2):return {'p1': pointCorner1, 'p2': pointCorner2}else:if self.isStraightLink(p1, pointCorner1) and self.isStraightLink(pointCorner1, pointCorner2) and self.isStraightLink(pointCorner2, p2) and self.isEmptyInMap(pointCorner1) and self.isEmptyInMap(pointCorner2):return {'p1': pointCorner1, 'p2': pointCorner2}# 横向判断for x in range(-1, self.__gameSize + 1):pointCorner1 = Point(x, p1.y)pointCorner2 = Point(x, p2.y)if x == p1.x or x == p2.x:continueif x == -1 or x == self.__gameSize:if self.isStraightLink(p1, pointCorner1) and self.isStraightLink(pointCorner2, p2):return {'p1': pointCorner1, 'p2': pointCorner2}else:if self.isStraightLink(p1, pointCorner1) and self.isStraightLink(pointCorner1, pointCorner2) and self.isStraightLink(pointCorner2, p2) and self.isEmptyInMap(pointCorner1) and self.isEmptyInMap(pointCorner2):return {'p1': pointCorner1, 'p2': pointCorner2}class Point():def __init__(self, x, y):self.x = xself.y = ydef isUserful(self):if self.x >= 0 and self.y >= 0:return Trueelse:return False'''判断两个点是否相同'''def isEqual(self, point):if self.x == point.x and self.y == point.y:return Trueelse:return False'''克隆一份对象'''def clone(self):return Point(self.x, self.y)'''改为另一个对象'''def changeTo(self, point):self.x = point.xself.y = point.y'''显示坐标'''def __repr__(self):return f"x={self.x},y={self.y}"MainWindow()

import os
import math
from PIL import Imagedef merge_images(image_folder, output_file, n, m):# 获取所有图像文件的列表image_files = [os.path.join(image_folder, f) for f in os.listdir(image_folder) if f.endswith('.png')]# 计算每个小图像的大小和大图像的大小image_count = len(image_files)if image_count == 0:print('No image files found in the directory:', image_folder)return# 计算小图像的大小以及大图像的大小img = Image.open(image_files[0])
#     img_size0 = img.size[0]
#     img_size1 = img.size[1]img_size0 = 40img_size1 = 40new_img_size0 = img_size0 * nnew_img_size1 = img_size1 * m# 创建一个新的大图像new_img = Image.new('RGB', (new_img_size0, new_img_size1), 'white')# 将所有小图像粘贴到新图像的正确位置for i, f in enumerate(image_files):row = int(i / n)col = i % nimg = Image.open(f)img = img.resize((img_size0, img_size1))new_img.paste(img, (col * img_size0, row * img_size1))# 保存大图像new_img.save(output_file)# 用法示例
image_folder = 'C:/Users/Administrator/Desktop/图标/卡通' #目录下放25张png图片
output_file = 'C:/Users/Administrator/Desktop/图标/卡通/new5.png'#运行程序合成一张图
n = 25  # 每行显示的图像数
m = 1  # 每列显示的图像数
merge_images(image_folder, output_file, n, m)