SQL123 SQL类别高难度试卷得分的截断平均值

题目

在这里插入图片描述

自测代码

drop table if exists examination_info;
CREATE TABLE  examination_info (id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',exam_id int UNIQUE NOT NULL COMMENT '试卷ID',tag varchar(32) COMMENT '类别标签',difficulty varchar(8) COMMENT '难度',duration int NOT NULL COMMENT '时长',release_time datetime COMMENT '发布时间'
)CHARACTER SET utf8 COLLATE utf8_general_ci;drop table if exists exam_record;
CREATE TABLE exam_record (id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',uid int NOT NULL COMMENT '用户ID',exam_id int NOT NULL COMMENT '试卷ID',start_time datetime NOT NULL COMMENT '开始时间',submit_time datetime COMMENT '提交时间',score tinyint COMMENT '得分'
)CHARACTER SET utf8 COLLATE utf8_general_ci;INSERT INTO examination_info(exam_id,tag,difficulty,duration,release_time) VALUES(9001, 'SQL', 'hard', 60, '2020-01-01 10:00:00'),(9002, '算法', 'medium', 80, '2020-08-02 10:00:00');INSERT INTO exam_record(uid,exam_id,start_time,submit_time,score) VALUES
(1001, 9001, '2020-01-02 09:01:01', '2020-01-02 09:21:01', 80),
(1001, 9001, '2021-05-02 10:01:01', '2021-05-02 10:30:01', 81),
(1001, 9001, '2021-06-02 19:01:01', '2021-06-02 19:31:01', 84),
(1001, 9002, '2021-09-05 19:01:01', '2021-09-05 19:40:01', 89),
(1001, 9001, '2021-09-02 12:01:01', null, null),
(1001, 9002, '2021-09-01 12:01:01', null, null),
(1002, 9002, '2021-02-02 19:01:01', '2021-02-02 19:30:01', 87),
(1002, 9001, '2021-05-05 18:01:01', '2021-05-05 18:59:02', 90),
(1003, 9001, '2021-02-06 12:01:01', null, null),
(1003, 9001, '2021-09-07 10:01:01', '2021-09-07 10:31:01', 50);

解题思路：

SELECTtag,difficulty,ROUND((CASEWHEN COUNT(score) > 2 THEN (SUM(score) - MAX(score) - MIN(score)) / (COUNT(score) - 2) # 必须使用count(字段)计数因为存在socre为空值的记录ELSE NULL -- 或者您可以选择一个默认值，比如0  END),1) AS clip_avg_score
FROMexam_record aLEFT JOIN examination_info b ON a.exam_id = b.exam_id
WHEREb.difficulty = 'hard' -- 将条件移到JOIN之后立即应用，以确保只考虑相关的examination_info记录  
GROUP BYtag,difficulty
HAVINGCOUNT(score) > 2;-- 确保分母不为零