题目描述

题解思路

我们遍历长度为k的窗口，我们只需要记录窗口内的最大和即可，遍历过程中刷新最大值

结果为窗口长度为k的最大和 除以 k

题解代码

impl Solution {pub fn find_max_average(nums: Vec<i32>, k: i32) -> f64 {let mut sum = 0;// 填满长度为k的窗口for i in 0..k as usize {sum += nums[i];}let mut max_sum = sum;// 移动窗口，并记录最大的窗口和for i in k as usize..nums.len() {sum += nums[i] - nums[i - k as usize];max_sum = max_sum.max(sum);}max_sum as f64 / k as f64}
}

题目链接

https://leetcode.cn/problems/maximum-average-subarray-i/description/