题目：

题解：

class Solution:def isMatch(self, s: str, p: str) -> bool:m, n = len(s), len(p)dp = [False] * (n+1)# 初始化dp[0] = Truefor j in range(1, n+1):if p[j-1] == '*':dp[j] = dp[j-2]# 状态更新for i in range(1, m+1):dp2 = [False] * (n+1)           # 滚动数组for j in range(1, n+1):if s[i-1] == p[j-1] or p[j-1] == '.':dp2[j] = dp[j-1]elif p[j-1] == '*':if s[i-1] != p[j-2] and p[j-2] != '.':dp2[j] = dp2[j-2]else:dp2[j] = dp2[j-2] | dp[j]dp = dp2                        # 滚动数组if sum(dp) == 0:                # 提前结束return Falsereturn dp[n]